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35b^2+18b-8=0
a = 35; b = 18; c = -8;
Δ = b2-4ac
Δ = 182-4·35·(-8)
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1444}=38$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-38}{2*35}=\frac{-56}{70} =-4/5 $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+38}{2*35}=\frac{20}{70} =2/7 $
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